Question

determine um número tal que seu quadrado diminuido do seu dobro e igual a 24​

Answer 1

$x^{2} -2x=24$

$x^{2} -2x-24=0$

$a=1$

$b=-2$

$c=-24$

$\Delta=b^{2} -4ac$

$\Delta=(-2)^{2} -4.(1).(-24)$

$\Delta=4+96$

$\Delta=100$

$x=\frac{-b\:\pm\:\sqrt{\Delta} }{2a}$

$x=\frac{-(-2)\:\pm\:\sqrt{100} }{2.(1)}$

$x=\frac{2\:\pm\:10}{2}$

$x_{1} =\frac{12}{2}=6$

$x_{2} =\frac{-8}{2}=-4$

$RESPOSTA=>6$

Answer 2

x^2 - 2x = 24
x^2 - 2x - 24 = 0
(x-6)(x+4)=0
x=6
x=-4