Question

DETERMINE TGX SABENDO QUE 3π/2 ≤ X ≤ 2π E SEN = -5/13

Answer 1

sen x = -5/13
sen²x + cos²x = 1
(-5/13)² + cos²x = 1
cos²x = 1 - 25/169
cos²x = 169/169 - 25/169
cos²x = 144/169
cos x = \/(144/169)
cos x = 12/13
tg x = sen x / cos x
tg x = (-5/13) / (12/13)
tg x = -5/12
3º quadrante: tg x = 5/12