Question

Determine sen,cos,tg :

Answer 1

Sendo sen = cateto oposto/hipotenusa
           cos = cateto adjacente/hipotenusa
           tg = cateto oposto/cateto adjacente

a - sen = 5/13
     cos = 12/13
     tg = 5/12

b - sen = 6/2√10 = 3/√10 x √10/√10 = 3√10/10
     cos = 2/2√10 = 1/√10 x √10/√10 = √10/10
     tg = 6/2 = 3

c - sen = 10/5√13 = 2/√13 x √13/√13 = 2√13/13
     cos = 15/5√13 = 3√13 x √13/√13 = 3√13/13
     tg = 10/15 = 2/3