Question

determine sen b, cos b, e tan b:

Answer 1

Sen(b)= cateto oposto ÷ hipotenusa
Sen (b)= 12/15 ---> 4/5

Cos(b)= cateto adjacente ÷ hipotenusa
Cos (b) = 9/15----> 3/5

Tan(b)= Sen(b) ÷ Cos(b)
Tan (b) = 4/3