Question

Determine
perimetro de um triangulo
retangulo cujo os
lados São : 5√27+3√75+√12​

Answer 1

$5\sqrt{27} + 3\sqrt{75} + \sqrt{12}\\5\sqrt{3^3} + 3\sqrt{5^2 * 3} + \sqrt{2^2 * 3}\\5\sqrt{3^2 * 3} + 3*5\sqrt{3} + 2\sqrt{3}\\5*3\sqrt{3} + 3*5\sqrt{3} + 2\sqrt{3}\\15\sqrt{3} + 15\sqrt{3} + 2\sqrt{3} = 32\sqrt{3}$