Question

Determine p de modo que f(x)= px²-(p-1)x possua raízes reais e iguais

Answer 1

$\Large\boxed{\begin{array}{l}\sf f(x)=px^2-(p-1)x\\\sf\Delta=b^2-4ac\\\sf\Delta=(-(p-1))^2-4\cdot p\cdot0\\\sf\Delta=(-1)^2\cdot(p-1)^2\\\sf\Delta=(p-1)^2.\\\sf Para\,ter\,duas\,ra\acute izes\,reais\,e\,iguais\\\sf devemos\,impor\,que\,\Delta=0.\\\sf DA\acute I\\\sf (p-1)^2=0\\\sf p-1=0\\\sf p=1\end{array}}$