Question

Determine os zeros e as coordenadas do vértice de cada função E representa graficamente y=x^(2)+6x+5

Answer 1

Δ = 6² - 4 * 1 * 5 = 36 - 20 = 16

$x_1=\frac{-6+\sqrt{16}}{2}= \frac{-6+4}{2}=-1\\ \\x_2=\frac{-6-\sqrt{16}}{2}= \frac{-6-4}{2}=-5$

Vertice:

$(x , y) = \left(-\frac{b}{2a},-\frac{\Delta}{4a}\right)\\\\(x,y) = \left(-\frac{6}{2},-\frac{16}{4}\right)\\\\(x,y)=(-3 , -4)$