Question

determine os zeros das seguintes funções f(x) =x^2 -36
f(x) = 6x^2 -5x +1

Answer 1

x^2-36=0
x^2=0+36
x^2=36
x= raiz de 36
x=-/+ 6
S={-6, +6}
6x^2-5x+1=0
delta=b^2-4ac
delta=(-5)^2-4.6.1
delta=25-24
delta=1
x=-b-/+ raiz de delta/2a
x=-(-5)-1/2.6
x=5-1/12
x=4/12 (÷4)
x=1/3
x=-(-5)+1/2.6
x=5+1/12
x=6/12 (÷6)
x=1/2
S={(1/2, 1/3)}