Question

determine os zeros da função f(x) = x2 - 6x + 5

Answer 1

Oi...

f(x) = x² - 6x + 5

f(x) = 0

$x^2-6x+5=0\\\\Coeficientes:\;a=1,\;b=-6\;e\;c=5\\\\\Delta=b^2-4ac\\\Delta=-6^2-4\cdot1\cdot(+5)\\\Delta=36-20\\\Delta=16\\\\x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\\x=\dfrac{6\pm\sqrt{16}}{2\cdot1}\\\\x=\dfrac{6\pm4}{2}\\\\x_1=\dfrac{6+4}{2}=\dfrac{10}{2}=5\\\\x_2=\dfrac{6-4}{2}=\dfrac{2}{2}=1$

Espero ter ajudado.