Question

Determine os valores desconhecidos em cada igualdade:

a) ( x/2, 7-y ) = ( 2, 2y - 1 )

b) (3, 2y -5 / 5) = ( x+2 , 2/ 3 )

Answer 1

A) ($\frac{x}{2}$,7-y) = (2, 2y-1)

$\left \{ {{\frac{x}{2} =2} \atop {7-y=2y-1}} \right.$

$\left \{ {{\frac{x}{2} =2} \atop {-y=-8}} \right.$

$\left \{ {{x=4} \atop {y=8}} \right.$

(4,8)

B) (3, $\frac{2y-5}{5}) = (x+2,\frac{2}{3})$

$\left \{ {{3=x+2} \atop {\frac{2y-5}{5} =\frac{2}{3} }} \right.$

$\left \{ {{x=3-2} \atop {6y-15=10}} \right.$

$\left \{ {{x=3-2} \atop {6y=15+10}} \right.$

$\left \{ {{6y=\frac{25}{6} } \atop {x=1}} \right.$

(1,$\frac{25}{6}$)

Answer 2

Resposta:

Devemos igualar X1 com X2 e Y1 e Y2

(X1, Y1) = (X2, Y2)

X/4 = 2 e 7 - Y = 2Y - 1

X = 8 e Y = 3/8