Question

Determine os valores de x que pode assumir nas seguintes equações do 2 grau:
a)
$x {}^{2} - 169 = 0$
b)
$x {}^{2} + 2x - 4 = 0$
c)
$6x {}^{2} - 3x = 0$
d)
$x {}^{2} + 2x = 0$
​

Answer 1

$\large\boxed{\boxed{\boxed{{Ol\'a}}}}}$

$A)\:x^2-169=0$

$x^2=169$

$x=±\sqrt{169}$

$x=±13$$\checkmark$






$B)\:x^2+2x-4=0$

$a=1;b=2;c=-4$

$\LARGE{x_{1},_{2}=\frac{-b±\sqrt{b^2-4.a.c}}{2.a}}$

$\LARGE}x_{1},_{2}=\frac{-2±\sqrt{2^2-4.1.(-4)}}{2.1}}$

$\LARGE{x_{1},_{2}=\frac{-2±\sqrt{4+16}}{2}}$

$\LARGE{x_{1},_{2}=\frac{-2±\sqrt{20}}{2}}$





$C)\:6x^-3x=0$

$x(6x-3)=0$

$x=0\:\:V\:6x-3=0$

$x=0\:\:V\:6x=3$

$x=0\:\:V\:x=\frac{3}{6}$





$D)\:x^2+2x=0$

$x(x+2)=0$

$x=0\:\:V\:x+2=0$

$x=0\:\:V\:x=-2$





qualquer dúvida comente.

08.04.2019