Question

Determine os valores de X e Y nos triângulos.

Answer 1

Boa noite!

a)
$\dfrac{20}{y}=\dfrac{16}{20+12}=\dfrac{12}{x}\\\dfrac{20}{y}=\dfrac{16}{32}=\dfrac{1}{2}\\y=20\cdot 2\\\boxed{y=40}\\\dfrac{12}{x}=\dfrac{16}{32}=\dfrac{1}{2}\\x=12\cdot 2\\\boxed{x=24}$

b)
$\dfrac{y}{34}=\dfrac{10}{30}=\dfrac{x}{16}\\\dfrac{y}{34}=\dfrac{1}{3}\\\boxed{y=\dfrac{34}{3}}\\\dfrac{x}{16}=\dfrac{1}{3}\\\boxed{x=\dfrac{16}{3}}$

Espero ter ajudado!