Question

Determine os valores aproximados de tg ( π-a ), tg ( π + a ), tg (2π - a )

Answer 1

$\boxed{Tg( \pi - a) = \frac{Tq \pi -Tg a}{1+Tg \pi *Tga}}$
$\boxed{Tg( \pi - a) = \frac{0 -Tg a}{1+0 *Tga}}$
$\boxed{Tg( \pi - a) = \frac{0 -Tg a}{1+0}}$
$\boxed{Tg( \pi - a) = \frac{-Tg a}{1}}$
$\boxed{\boxed{Tg( \pi - a) = -Tg a}}$

$\boxed{Tg( \pi + a) = \frac{Tq \pi +Tg a}{1-Tg \pi *Tga}}$
$\boxed{Tg( \pi + a) = \frac{0 +Tg a}{1-0 *Tga}}$
$\boxed{Tg( \pi + a) = \frac{0 +Tg a}{1-0}}$
$\boxed{Tg( \pi + a) = \frac{Tg a}{1}}$
$\boxed{\boxed{Tg( \pi + a) = Tg a}}$

$\boxed{Tg( 2\pi - a) = \frac{Tq 2\pi -Tg a}{1+Tg 2\pi *Tga}}$
$\boxed{Tg( 2\pi - a) = \frac{0 -Tg a}{1+0 *Tga}}$
$\boxed{Tg( 2\pi - a) = \frac{0 -Tg a}{1+0}}$
$\boxed{Tg( 2\pi - a) = \frac{-Tg a}{1}}$
$\boxed{\boxed{Tg( 2\pi - a) = -Tg a}}$

Acho que é isso