Question

determine os seis primeiros termos da sequencia cujo o termo geral e:  
n + 1    
2    2

Answer 1

$a_1=\frac{1}{2}+\frac{1}{2}=1\\ \\ a_2=\frac{2}{2}+\frac{1}{2}=\frac{3}{2}\\ \\ a_3=\frac{3}{2}+\frac{1}{2}=2\\ \\ a_4=\frac{4}{2}+\frac{1}{2}=\frac{5}{2}\\ \\ a_5=\frac{5}{2}+\frac{1}{2}=3\\ \\ a_6=\frac{6}{2}+\frac{1}{2}=\frac{7}{2}$

Answer 2

$\boxed{a_n= \frac{n+1}{2}}$

$\boxed{a_1= \frac{1+1}{2} = 1}$

$\boxed{a_2= \frac{2+1}{2} = \frac{3}{2} }$

$\boxed{a_3= \frac{3+1}{2} = 2}$

$\boxed{a_4= \frac{4+1}{2} = \frac{5}{2} }$

$\boxed{a_5= \frac{5+1}{2} = 3}$

$\boxed{a_6= \frac{6+1}{2} = \frac{7}{2} }$

Espero ter ajudado. :))