Determine os numeros reais x e y na igauldade: ![\left[\begin{array}{ccc}5x&-2y&-4\\6x&+4y&-11\end{array}\right] = \left[\begin{array}{ccc}26&-4&\4&12&-11\end{array}\right]](https://tex.z-dn.net/?f=+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5x%26amp%3B-2y%26amp%3B-4%5C%5C6x%26amp%3B%2B4y%26amp%3B-11%5Cend%7Barray%7D%5Cright%5D+%3D+%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D26%26amp%3B-4%26amp%3B%5C4%26amp%3B12%26amp%3B-11%5Cend%7Barray%7D%5Cright%5D+ "\left[\begin{array}{ccc}5x&-2y&-4\\6x&+4y&-11\end{array}\right] = \left[\begin{array}{ccc}26&-4&\4&12&-11\end{array}\right]")
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Boa noite
5x - 2y = 26,
6x + 4y = 12
10x - 4y = 52
16x = 64
x = 4
20 - 2y = 26
2y = -6
y = -3
S = (4, -3)
5x - 2y = 26,
6x + 4y = 12
10x - 4y = 52
16x = 64
x = 4
20 - 2y = 26
2y = -6
y = -3
S = (4, -3)
Respondido por
1
5x - 2y = 26
6x + 4y = 12
10x 4y = 52
26x = 64
X= 64/16
X = 4
X =4
20- y = -26
2y = -6
Y = 6/2
Y = -3
A = (4, - 3)
6x + 4y = 12
10x 4y = 52
26x = 64
X= 64/16
X = 4
X =4
20- y = -26
2y = -6
Y = 6/2
Y = -3
A = (4, - 3)
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