Question

Determine os números inteiros positivos x,y e z, sabendo que: 9/12= 3/x,
12/y = x/3 e 4z-4/36 = x/y

Answer 1

9/12 = 3/x
9x = 12 * 3
9x = 36
x = 36/9
x = 4

12/y = 4/3
4y = 3*12
4y = 36
y = 36/4
y = 9

4z-4/36 = 4/9
(4z-4)*9 = 36*4
36z-36 = 144
36z = 144+36
36z = 180
z = 180/36
z = 5

Resposta: x = 4, y = 9 e z = 5.