Matemática, perguntado por MarshallBruce, 1 ano atrás

Determine os 7 primeiros termos da raiz abaixo onde n Є N :
A) an=2n
b)an=4n+2
C) an=3n -1
D) an =4n
E) an=5n+2
f) an=2n+2n
g)an=6n+2

Soluções para a tarefa

Respondido por TesrX
1
Olá.
A
\boxed{\ \ a_n=2n\ \ }

a_1=2\cdot1=\boxed{2}
a_2=2\cdot2=\boxed{4}
a_3=2\cdot3=\boxed{6}
a_4=2\cdot4=\boxed{8}
a_5=2\cdot5=\boxed{10}
a_6=2\cdot6=\boxed{12}
a_7=2\cdot7=\boxed{14}


B
\boxed{\ \ a_n=4n+2\ \ }

a_1=4\cdot1+2=4+2=\boxed{6}
a_2=4\cdot2+2=8+2=\boxed{10}
a_3=4\cdot3+2=12+2=\boxed{14}
a_4=4\cdot4+2=16+2=\boxed{18}
a_5=4\cdot5+2=20+2=\boxed{22}
a_6=4\cdot6+2=24+2=\boxed{26}
a_7=4\cdot7+2=28+2=\boxed{30}

C
\boxed{\ \ an=3n-1\ \ }

a_1=3\cdot1-1=3-1=\boxed{2}
a_2=3\cdot2-1=6-1=\boxed{5}
a_3=3\cdot3-1=9-1=\boxed{8}
a_4=3\cdot4-1=12-1=\boxed{11}
a_5=3\cdot5-1=15-1=\boxed{14}
a_6=3\cdot6-1=18-1=\boxed{17}
a_7=3\cdot7-1=21-1=\boxed{20}


D
\boxed{\ \ a_n=4n\ \ }

a_1=4\cdot1=\boxed{5}
a_2=4\cdot2=\boxed{8}
a_3=4\cdot3=\boxed{12}
a_4=4\cdot4=\boxed{16}
a_5=4\cdot5=\boxed{20}
a_6=4\cdot6=\boxed{24}
a_7=4\cdot7=\boxed{28}


E
\boxed{\ \ a_n=5n+2\ \ }

a_1=5\cdot1+2=5+2=\boxed{7}
a_2=5\cdot2+2=10+2=\boxed{12}
a_3=5\cdot3+2=15+2=\boxed{17}
a_4=5\cdot4+2=20+2=\boxed{22}
a_5=5\cdot5+2=25+2=\boxed{27}
a_6=5\cdot6+2=30+2=\boxed{32}
a_7=5\cdot7+2=35+2=\boxed{37}


F
\boxed{\ \ a_n=2n+2n\ \ }

a_1=4\cdot1=\boxed{4}
a_2=4\cdot2=\boxed{8}
a_3=4\cdot3=\boxed{12}
a_4=4\cdot4=\boxed{16}
a_5=4\cdot5=\boxed{20}
a_6=4\cdot6=\boxed{24}
a_7=4\cdot7=\boxed{28}


G
\boxed{\ \ a_n=6n+2\ \ }

a_1=6\cdot1+2=6+2=\boxed{8}
a_2=6\cdot2+2=12+2=\boxed{14}
a_3=6\cdot3+2=18+2=\boxed{20}
a_4=6\cdot4+2=24+2=\boxed{26}
a_5=6\cdot5+2=30+2=\boxed{32}
a_6=6\cdot6+2=36+2=\boxed{38}
a_7=6\cdot7+2=42+2=\boxed{44}

Qualquer dúvida, deixe nos comentários.
Bons estudos.
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