Question

determine o zero da função
$x {}^{2} + 6x + 5$

Answer 1

x²+6x+5
Δ=6²-4.1.5 ⇒ Δ=36-20 ⇒ Δ =16 ⇒√Δ =4
x¹= $\frac{-6+4}{2}$ ⇒ x¹=-1
x²= $\frac{-6-4}{2}$ ⇒ x²= -5