Question

Determine o zero da função:
3x^2-11x-4
Calcular a função nos pontos:(-3,-2,-1,0,1,2,3)

Answer 1

3x^2 - 11x -4 = 0
a=3; b = -11; c = -4
/\= b^2-4ac
/\= (-11)^2 - 4.3.(-4)
/\= 121 + 48
/\= 169
x= (-b +/- V/\)/2a
x= [-(-11)+13]/2.3
x= 24/6
x'= 4

x= (11-13)/6
x" = -2/6 (:2)/(:2)
x" = -1/3


F(x) = 3x^2 -11x-4
F(3) = 3.3^2 - 11.3 - 4 = 3.9 - 33 - 4 = 27-37 = - 10
F(2) = 3.2^2-11.2-4 = 3.4-22-4= 12-26 = -14
F(1) = 3.1^2-11.1-4 = 3-11-4 = 3-15= - 12
F(0) = 3.0^2 - 11.0 - 4 = - 4
F(-1) = 3.(-1)^2 -11.(-1) - 4 = 3+11-4 = 14-4= 10
F(-2) = 3.(-2)^2-11.(-2) -4 = 3.4+22-4= 12+18= 30
F(-3) = 3.(-3)^2 -11.(-3) - 4 = 3.9+33-4= 27+29= 56