Question

determine o vertice v da parabola que representa a funçao y=x²-4x-5

Answer 1

$\boxed{V(Xv,~Yv)}$

$\boxed{Xv= \frac{-b}{2.a} }\\\\Xv= \frac{-(-4)}{2.1a}\\\\Xv= \frac{4}{2}\\\\\boxed{Xv=2}$

$\Delta=b^2-4.a.c\\\Delta=(-4)^2-4.1.(-5)\\\Delta=16+20\\\Delta=36\\\\\boxed{Yv= \frac{-\Delta}{4.a}}\\\\Yv= \frac{-36}{4.1} \\\\Yv= \frac{-36}{4.1} \\\\\boxed{Yv=-9}$

$V\'ertice:\\\\\boxed{V(2,~-9)}$