Question

determine o vertice das função:
y=x^2-9 ​

Answer 1

x²-9=0

a=1

b=0

c=-9

∆=b²-4ac

∆=0²-4*1*-9

∆=0+36

∆=36

Xv=-b/2a

Xv=-0/2*-9

Xv=-0/-18

Xv=0

Yv=-∆/4a

Yv=-36/4*1

Yv=-36/4

Yv=-9

Vértice =>{ 0 e -9}