Question

determine o vertice √ da parabola que representa a funcao quadratica

a) f (x) = x² - 2x - 3
b) f (x) = -x² + 3x -5
c) f (x) = x² -4x + 3

Answer 1

Vértice da parábola = - ∆/4a, -b/2a
a)
-b²-4.a.c/4a
-2²- 4.1.(-3)
4 + 12
∆ = 16 -> -16/4.1
= -4
-b/2a = -(-2)/2
= 1.
s= (1,-4)

b)
-b²-4.a.c/4a
3²-4.(-1).(-5)
9 - 20
∆ = -11 -> -(-11)/4.(-1)
= 11/-4
= -2,75
-b/2a = -3/-1
= 3 .
s= (3,-2,75)

c)-b²-4.a.c/4a
-4²- 4.1.3
16 - 12
∆ = 4 -> -4/4.1
= -1
-b/2a = -(-4)/2.1
= 2.
s= (2,-1)

Espero ter ajudado. bom estudo!