Question

determine o vertice da parabola da equaçao: f(x)=x2-3x+2

Answer 1

$f(x)=x^2-3x+2\\x^2-3x+2=0\\\Delta=(3)^2-4.1.2\\\Delta=9-8\\\Delta=1$

Agora os vértices.

$X_V= \frac{-b}{2a}$

$\boxed{X_V= \frac{3}{2}}$

$X_Y= \frac{-\Delta}{4a}$

$\boxed{X_Y= -\frac{1}{4} }$