Question

Determine o vértice da função. y=x2-2x+3 ?

Answer 1

y = x² - 2x+ 3
v = -b/2a , - Δ/4a
v = - (-2)/2.1 , - (4+12)/4.1
v = 2/2, -8/4
v = 1, 2

Answer 2

As coordenadas (x, y) do vértice da parábola que representa uma função quadrática podem ser obtidas pelas seguintes razões:

$\fbox{ X_v=\dfrac{-b}{2a} }\\\\\fbox{ Y_v=\dfrac{-\Delta}{~4a} }~~lembrando~que~\Delta=b^2-4ac$

Portanto: 

$y=x^2-2x+3\\\\\\\Delta=(-2)^2-4\cdot1\cdot3\\\\\Delta=4-12\\\\\Delta=-8\\---------------------------\\\\\\X_v=\dfrac{-(-2)}{2\cdot1}\\\\\ X_v=\dfrac{2}{2}\\\\X_v=1\\---------------------------\\\\Y_v=\dfrac{-(-8)}{4\cdot1}\\\\Y_v=\dfrac{8}{4}\\\\Y_v=2\\---------------------------$

Coordenadas do vértice: (1, 2)