Question

Determine o vértice da função f(x) =2x²+3x + 1

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Answer 1

Oie, tudo bom?

f(x) = 2x² + 3x + 1

a = 2, b = 3, c = 1

∆ = b² - 4ac

∆ = 3² - 4 . 2 . 1

∆ = 9 - 8

∆ = 1

Xv = - b/2a

Xv = - 3/(2 . 2)

Xv = - 3/4

Yv = - ∆/4a

Yv = - 1/(4 . 2)

Yv = - 1/8

V(- 3/4 , - 1/8)

Att. NLE Top Shotta

Answer 2

V={-3/4; -1/8)

f(x)= 2x+3x+1

a=2, b=3 e c=1

Xv= -b/2a

Xv= -3/2.2

Xv= -3/4

$yv = \frac{ - (b {}^{2} - 4ac) }{4a}$

$yv = \frac{ - (3 {}^{2} - 4 \times 2 \times 1)}{4 \times 2} = \frac{ - (9 - 8)}{8} = \frac{ - 9 + 8}{8} = - \frac{1}{8}$