Question

Determine o valor  para que as sentenças se tornem verdadeiras.
​

Answer 1

Resposta:

a) $\Delta \cdot (-3x^2y^4) = 24x^5y^2$

$\Delta = \frac{24x^5y^2}{-3x^2y^4}\\\\\Delta = - \frac{8x^5y^2}{x^2y^4}\\\\\Delta = - \frac{8x^3}{y^2}$

b) $\Delta \cdot \Delta = 169b^6m^{10}$

$\Delta^2 = 169b^6m^{10}\\\\\Delta = \sqrt{169b^6m^{10}}\\\\\Delta =\sqrt{169}\sqrt{b^6}\sqrt{m^{10}}\\\\\Delta = 13\sqrt{\left(b^3\right)^2}\sqrt{\left(m^5\right)^2}\\\\\Delta = 13b^3m^5$

c) $\frac{12x^2y^8}{\Delta} = 4y^2$

$12x^2y^8 = 4y^2 \cdot \Delta\\\\\Delta = \frac{12x^2y^8}{4y^2}\\\\\Delta = \frac{3x^2y^8}{y^2} = 3x^2y^{8-2}\\\\\Delta = 3x^2y^6$