Question

Determine o valor numérico da função afim f(x)= 2x +1

f (1)
f(5)
f(2) +f (0)

Answer 1

f(x) = 2x + 1

a)
f(1) = 2*1 + 1
f(1) = 2 + 1
f(1) = 3


b)
f(5) = 2*5 + 1
f(5) = 10 + 1
f(5) = 11

c)
f(2) + f(0)

f(2) = 2 * 2 + 1
f(2) = 4 + 1
f(2) = 5


f(0) = 2 * 0 + 1
f(0) = 1


= f(2) + f(0)
= 5 + 1
= 6