determine o valor numerico da expressão: (sen2x-cos3x) / (tg(x/2)+cotgx) para x = pi/3
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(sen 2x - cos 3x)/(tg x/2 + cotg x) x = π/3
{sen 2(π/3) - cos 3(π/3)}/{tg (π/3)/2 + 1/tg(π/3)/2}
(sen 120° - cos 180°)/( tg 30° + 1/tg 30°)
{(√3/2 - (-1)}/(√3/3 + 1/√3/3)
(√3/2 + 1)/(√3/3 + 1/3√3)
(√3 + 2/2)/(9 + 1/3√3)
(√3 + 2/2)/(10/3√3) = √3 + 2/2 . 3√3/10 = 7√3/20
{sen 2(π/3) - cos 3(π/3)}/{tg (π/3)/2 + 1/tg(π/3)/2}
(sen 120° - cos 180°)/( tg 30° + 1/tg 30°)
{(√3/2 - (-1)}/(√3/3 + 1/√3/3)
(√3/2 + 1)/(√3/3 + 1/3√3)
(√3 + 2/2)/(9 + 1/3√3)
(√3 + 2/2)/(10/3√3) = √3 + 2/2 . 3√3/10 = 7√3/20
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