Question

Determine o valor dos seguintes logaritmos
a) log² 32
b) log¹/⁹3v3c) log⁷343
d) log⁹81​

Answer 1

Resposta:

Explicação passo-a-passo:

a)

log₂ 32 = x => 2ˣ = 32 => 2ˣ = 2⁵ => x = 5

b)

$log_{\frac{1}{9}}3\sqrt{3}=x=>(\frac{1}{9})^{x}=3\sqrt{3}=>(9^{-1})^{x}=\sqrt{3^{3}}=>[[(3)^{2}]^{-1}]^{x}=>(3^{-2})^{x}=3^{\frac{3}{2}}=>3{-2x}=3^{\frac{3}{2}}=>-2x=\frac{3}{2}=>x=\frac{3}{-2.2}=>x=-\frac{3}{4}$

c)

log₇ 343 = x => 7ˣ = 7³ => x = 3

d)

log₉ 81 = x => 9ˣ = 81 => 9ˣ = 9² => x = 2