Question

determine o valor do quociete 2-3i÷-1-i

Answer 1

$\frac{2-3i}{-1-i} = \frac{(2-3i)(-1+i)}{(-1-i)(-1+i)} =\frac{-2+2i+3i-3i^2}{1-i^2} = \frac{1+5i}{2} = \frac{1}{2} + \frac{5}{2} i$