Question

determine o valor de x utilizando o teorema de Pitágoras

Answer 1

a
a = x
b = 28
c = 21
x² = 28² + 21²
x² = 784   + 441
x² = 1225
x = V1225 = 35 ****

b
b =x + 3
c = 6
a = x + 5
a² = b² + c²
( x + 5)² = ( x + 3)² + 6² 
( x² + 2.x.5 + 5² ) =  ( x² + 2 .3.x + 3² ) + 36
x² + 10x + 25 = x² + 6x + 9 ) + 36
x² - x² + 10x - 6x + 25 - 9 - 36 =0
4x  - 20 = 0
4x = 20
x = 20/4 = 5 ****
x + 5 = 5 + 5  =10 ***  ( a)
x + 3 = 5 + 3 = 8 ***  ( b )
c
b = 24
c = x
a = 25
25² + 24² + x² 
625 = 576 + x² 
625 - 576 = x² 
x² = 49
x = V49 = 7 ***  ( c )
d
a = 20
b = 3x 
c = 4x
20² = ( 3x)² + ( 4x)²
400 = 9x² + 16x²
25x² = 400
x² = 400/25 =
x = V16 = 4 ****

3x = 3(4) = 12 ****   ( b )
4x = 4(4) = 16 *** 9 c )