Determine o valor de x para que existam os logaritmos abaixo: a)log(2x-4)32 b)log3(3x-12)
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a) log(2x-4)32= x
![log_{(2x-4)} 32=b \\
(2x-4)^{b} =32 \\
(2x-4)^{b} = 2^{5} \\
b=5; \\ 2x-4=2 \\ 2x=6 \\ x=3 log_{(2x-4)} 32=b \\
(2x-4)^{b} =32 \\
(2x-4)^{b} = 2^{5} \\
b=5; \\ 2x-4=2 \\ 2x=6 \\ x=3](https://tex.z-dn.net/?f=log_%7B%282x-4%29%7D+32%3Db+%5C%5C+%0A+%282x-4%29%5E%7Bb%7D+%3D32+%5C%5C+%0A+%282x-4%29%5E%7Bb%7D+%3D+2%5E%7B5%7D++%5C%5C+%0Ab%3D5%3B+%5C%5C+2x-4%3D2+%5C%5C+2x%3D6+%5C%5C+x%3D3)
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