Question

Determine o valor de x para o qual (4/9)^{x}=(81/16).[/tex]

Answer 1

$\left( \frac{4}{9} \right)^x=\frac{81}{16} \\ \\ \left( \frac{4}{9} \right)^x=\frac{9^2}{4^2} \\ \\ \left( \frac{4}{9} \right)^x=\left(\frac{9}{4} \right)^2 \\ \\ \left( \frac{4}{9} \right)^x=\left(\frac{4}{9} \right)^{-2} \\ \\ \boxed{x=-2}$