Question

determine o valor de x nos triângulos retângulos URGENTE

Answer 1

Teorema de Pitágoras:

${h}^{2} = {c}^{2} + {c}^{2} \\ \\ h = \sqrt{ {c}^{2} + {c}^{2} } \\ c = \sqrt{ {h}^{2} - {c}^{2} }$

a)

$x = \sqrt{ {6}^{2} + {8}^{2} } \\ x = \sqrt{36 + 64} \\ x = \sqrt{100} \\ x = 10$

b)

$x = \sqrt{ {9}^{2} + {12}^{2} } \\ x = \sqrt{81 + 144} \\ x = \sqrt{225 } \\ x = 15$

c)

$x = \sqrt{ {5}^{2} - {4}^{2} } \\ x = \sqrt{25 - 16} \\ x = \sqrt{9} \\ x = 3$

d)

${20}^{2} = {(3x)}^{2} + {(4x)}^{2} \\ 400 = {9x}^{2} + {16x}^{2} \\ 400 = {25x}^{2} \\ {x}^{2} = \frac{400}{25} \\ x = \sqrt{ 16 } \\ x =4$

Espero ter ajudado (: