Question

Determine o valor de x nos triângulos retângulos.

Answer 1

Resposta:

D)

${x}^{2} = 18 \times 8 \\ {x}^{2} = 144 \\ x = \sqrt{144} \\ x = 12$

E)

${ \sqrt{38} }^{2} = {6}^{2} + {x}^{2} \\ 38 - 36 = {x}^{2} \\ x = \sqrt{2}$

F)

${18}^{2} = {x}^{2} + {x}^{2} \\ 324 = 2 {x}^{2} \\ {x}^{2} = \frac{324}{2} \\ {x}^{2} = 162 \\ x = \sqrt{162} \\ x = \sqrt{81 \times 2} \\ x = 9 \sqrt{2}$