Question

determine o valor de x no triângulo a seguir​

Answer 1

$\large\boxed{\begin{array}{l}\underline{\sf Pel\,lei\,dos\,cossenos\!:}\\\rm x^2=6^2+8^2-2\cdot6\cdot8\cdot cos(60^\circ)\\\rm x^2=36+64-\backslash\!\!\!2\cdot6\cdot8\cdot\dfrac{1}{\backslash\!\!\!2}\\\\\rm x^2=100-48\\\rm x^2=52\\\rm x=\sqrt{52}\\\rm x=\sqrt{4\cdot13}\\\rm x=2\sqrt{13} \end{array}}$