Question

determine o valor de x nas igualdades
$\sqrt{ {4}^{x} } \div \sqrt{2} = 4 \sqrt{2}$
$\sqrt{550} \div \sqrt{11} = x \sqrt{2}$
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Answer 1

$\frac{\sqrt{(2)^{2x}} }{\sqrt{2}} = 4\sqrt{2}\\\\2^{x} = \sqrt{2} * 4\sqrt{2}\\2^{x} = 4 * 2\\2^{x} = 2^{3}\\x = 3\\\\\\ \frac{\sqrt{11 * 25 * 2}}{\sqrt{11}} = x\sqrt{2} \\\\\sqrt{2 * 25} = x\sqrt{2}\\ 5\sqrt{2} = x\sqrt{2}\\ 5 = x$