Question

Determine o valor de X nas igualdades.

A) Raiz de 34 . Raiz de 8 = 4 raiz de X

B) Raiz de X . Raiz de 40 = 8 raiz de 10

C) Raiz de 4 elevado a X : raiz de 2 = 4 raiz de 2

D) raiz de 550 : raiz de 11 = X raiz de 2

Me ajudem pfv !!!

Answer 1

a) √34×√8=4√x

√34×8=√16x

√272=√16x (corta as raízes)

16x=272

x=272/16

x= 17

b) √x×√40=8√10

√x×40=√640

√40x=√640 (elimina as raízes)

40x=640

x=640/40

x=16

 

c) √4ˣ÷√2=9√2

√4ˣ÷2=√162 (corta as raízes)

4ˣ÷2=162

4ˣ=162×2

4ˣ=324

d) √550÷√11=x√2

√550÷11=√2x²

√50=√2x² (elimine as raízes)

2x²=50

x²=50/2

x²=25

x=√25

x=5

Answer 2

Resposta:

Letra A-x=17