Question

DETERMINE O VALOR DE x NAS FIGURAS



ps: preciso da conta ​

Answer 1

Explicação passo-a-passo:

$\frac{x}{sen30} = \frac{5 \sqrt{2} }{sen45}$

$\frac{x}{ \frac{1}{2} } = \frac{5 \sqrt{2} }{ \frac{ \sqrt{2} }{2} }$

$x \times \frac{2}{1} = 5 \sqrt{2} \times \frac{2}{ \sqrt{2} }$

$2x = \frac{10 \sqrt{2} }{ \sqrt{2} }$

$2x = 10$

$x = \frac{10}{2}$

$x = 5$

......

${a}^{2} = {b}^{2} + {c}^{2} - 2 \times b \times c \times cos \alpha$

${x}^{2} = {4}^{2} + {8}^{2} - 2 \times 4 \times 8 \times cos60$

${x}^{2} = 16 + 64 - 64 \times \frac{1}{2}$

${x}^{2} = 80 - \frac{64}{2}$

${x}^{2} = 80 - 32$

${x}^{2} = 48$

$x = \sqrt{48}$

$x = 4 \sqrt{3}$