Question

determine o valor de x na função expotencial de
${81}^{x - 2 = \sqrt[4]{27} }$
​

Answer 1

Explicação passo-a-passo:

${81}^{x - 2} = \sqrt[4]{27}$

${81}^{x - 2} = {27}^{ \frac{1}{4} }$

${( {3}^{4}) }^{x - 2} = { {(3}^{3}) }^{ \frac{1}{4} }$

${3}^{4 \times x + 4 \times (- 2)} = {3}^{3 \times \frac{1}{4} }$

${3}^{4x - 8} = {3}^{ \frac{3}{4} }$

$4x - 8 = \frac{3}{4}$

$\frac{4 \times 4x}{4} - \frac{4 \times 8}{4} = \frac{3}{4}$

$\frac{16x}{4} - \frac{32}{4} = \frac{3}{4}$

$16x - 32 = 3$

$16x = 3 + 32$

$16x = 35$

$x = \frac{35}{16}$