Matemática, perguntado por gabriel23617, 9 meses atrás

Determine o Valor de X na equação a seguir.

a)
\frac{3x}{2} - 5 = \frac{x}{4}

b)
\frac{x}{2} + 5 = \frac{2x}{3} - x

c)
\frac{x}{3} + (x - 2) = \frac{x}{2} + (x - 3)

Preciso da conta completa!

Soluções para a tarefa

Respondido por Usuário anônimo
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Resposta:

OLÁ

VAMOS A SUA PERGUNTA:⇒⇒

A:)→

\sf\dfrac{3x}{2}-5= \dfrac{x}{4}\\\\\sf2\times3x-20=x\\\\\sf 6x-20=x\\\\\sf 6x-20-x=0\\\\\sf 5x-20=0\\\\\sf 5x=20\\\\\sf x=\dfrac{20}{5}\\\\\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \red{x=4}}}}\ \checkmark

B:)→

\sf \dfrac{x}{2}+5= \dfrac{2x}{3}-x\\\\\sf3x+30=2\times2x-6x\\\\\sf 3x+30=4x-6x\\\\\sf 3x+30=-2x\\\\\sf 3x+30+2x=0\\\\\sf 5x+30=0\\\\\sf 5x=-30\\\\\sf x=\dfrac{-30}{5}\\\\\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \green{x=-6}}}}\ \checkmark

C:)→

\sf \dfrac{x}{3}+(x-2)= \dfrac{x}{2}+(x-3)\\\\\sf 2x+6x-12=3x+6x-18\\\\\sf 8x-12=3x+6x-18\\\\\sf 8x-12=9x-18\\\\\sf 8x-12-9x=-18\\\\\sf -x-12=-18\\\\\sf -x=-18+12\\\\\sf -x=-6\\\\\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \orange{x=6}}}}\checkmark

Explicação passo-a-passo:

ESPERO TER AJUDADO

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