Question

Determine o valor de x na equação:

Answer 1

log2 (logx 16) = 3
log2 (logx 16) = log2 8
logx 16 = 8

x^8 = 16
$x = \sqrt[8]{16}$
$x = {16}^{ \frac{1}{8} } \\ x = ( { {2}^{4} )}^{ \frac{1}{8} } \\ x = {2}^{ \frac{1}{2} } \\ x = \sqrt{2}$