Question

Determine o valor de X. Façam passo a passo!!!!

Answer 1

$\sqrt{5} \frac{ 2^{x}+4 }{3} -1=2 \sqrt{} \frac{5( 2^{x}+4) }{3}-1=2 \sqrt{} \frac{5x 2^{x}+20 }{3}-1=2 \sqrt{} \frac{5x 2^{x}+20 }{3}-2+1 \sqrt{} \frac{5x 2^{x}+20 }{3}-3 \sqrt{} \frac{5x 2^{x}+20 }{3}- 3^{2} \sqrt{} \frac{5x 2^{x}+20 }{3}9$
5x2+20/3=9
3x 5x2+20/3=3x9
5x2+20=27
5x2+20-20=27-20
5x2=24-20
5x2=7
5x2÷5=7÷5
2=7÷5
x=log2(7/5)