Question

determine o valor de x em cada triângulo
AJUDA por favor ​

Answer 1

Resposta:

$a)90 + x + 17 + x + 23 = 180 \\ 2x = 180 - 130 \\ 2x = 50 \\ x = \frac{50}{2} = 25 \\ b)x + 9 + 3x + x + 11 = 180 \\ 5x = 180 - 20 \\ 5x = 160 \\ x = \frac{160}{5} = 32 \\ c)2x + 2x + 12 + x + 8 = 180 \\ 5x = 180 - 20 \\ 5x = 160 \\ x = \frac{160}{5} = 32 \\ d)2x + 5 + 3x + 40 + 90 = 180 \\ 5x = 180 - 135 \\ 5x = 45 \\ x = \frac{45}{5} = 9 \\ e)2x + 12 + 2x + 28 + x + 20 = 180 \\ 5x = 180 - 60 \\ 5x = 120 \\ x = \frac{120}{5} = 24$