Question

Determine o valor de x em cada caso:

Answer 1

$a) \frac{3}{4x} = \frac{8}{x + 1} \\ 3(x + 1) = 32x \\ 3x + 3 - 32x = 0 \\ - 29x + 3 = 0 \\ - 29x = - 3 \\ 29x = 3 \\ x = \frac{3}{29} \\ \\ b) \frac{3}{4x} = \frac{8}{x - 1} \\ 3(x - 1) = 32x \\ 3x - 3 = 32x \\ 3x - 32x = 3 \\ - 29x = 3 \\ x = - \frac{3}{29} \\ \\ c) \frac{3}{4} = \frac{8}{x + 1} \\ 3(x + 1) = 32 \\ 3 x + 3 = 32 \\ 3x = 32 - 3 \\ 3x = 29 \\ x = \frac{29}{3} \\ \\ d) \frac{8}{4} = \frac{2x}{14} \\ 2 = \frac{2x}{14} \\ 2x = 28 \\ x = 14$