Question

Determine o valor de x em cada caso

Answer 1

Usando teorema de pitagoras.

14²=x²+(5V3)²
196=x²+25.V9
196=x²+25.3
196=x²+75
x²=196-75
x²=121
x=V121
x=11

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(V50)²=1²+x²
V2500=1+x²
50=1+x²
x²=50-1
x²=49
x=V49
x=7

Answer 2

${ \sqrt{50} }^{2} = 1 {}^{2} + x \\ 50 = 1 + x \\ 50 - 1 = x \\ 49 = x$

$14 {}^{2} = 5 \sqrt{3} {}^{2} + x \\ 196 = 5 \times 3 + x \\ 196 = 15 + x \\ 196 - 15 = x \\ 181 = x$