Question

Determine o valor de x, aplicando o teorema de Pitágoras..

Answer 1

a) x² = 3² + 1² → x² = 9 + 1 → x² = 10 → x = √10
b) 15² = x² + 12² → 225 = x² + 144 → 225 - 144 = x² → x² = 81 → x = √81 →
x = 9
c) x² = (2√2)² + 1² → x² = 4 . 2 + 1 → x² = 8 + 1 → x² = 9 → x = √9 → x = 3
d) (√17)² = x² + 1² → 17 = x² + 1 → 17 - 1 = x² → x² = 16 → x = √16 → x = 4
e) (6√2)² = x² + x² → 36 . 2 = 2x² → 72 = 2x² → 72 = x² → x² = 36 →
                                                                             2
continuando: x = √36 → x = 6