Question

determine o valor de X
a) 3x+2 [x+(x+11).3]=88
b)x+3 [2x+3 (x+4)]=20

Answer 1

a)3 x + 2 [x + (x + 11 ).3 ]=88
3 x + 2 [x + 3 x + 33] = 88
3 x + 2 [4 x + 33)] = 88
3 x + 8 x + 66  = 88
11 x + 66 = 88
11 x = 88 - 66
11 x = 22
x = 22/11
x = 2

b)x + 3 [2 x + 3 (x + 4 )] = 20
x + 3 [2 x + 3 x + 12 ] = 20
x + 3 [ 5 x + 12 ] = 20
x + 15 x + 36 = 20
16 x + 36 = 20
16 x = 20 - 36
16 x = -16
x = -16/16
x = -1