Question

Determine o valor de x

Answer 1

$\boxed{\begin{array}{l}\rm c) ~\sf8x=4^2\\\sf x=\dfrac{16}{8}\\\\\sf x=2\\\\\tt d) ~\sf (6+x) \cdot x=4^2\\\sf x^2+6x=16\\\sf x^2+6x-16=0\\\sf x^2-(2-8)x+2\cdot(-8)=(x+2)(x-8)\\\sf (x+2)(x-8)=0\\\sf x-8=0\implies x=8\end{array}}$