Question

Determine o valor de
Sen300°+2.cos120°-3.tg45

Answer 1

y = cos 120° + sen 300° - tg 135° - cos 90°

y = -cos(180-120°) + -sen(360-300°) - -tg(180-135°) - 0

y= -cos(60) -sen(60) +tg(45)

y = -1/2 -V3/2 +1

y = 1/2 - V3/2..........ou.....(1 -V3)/2